User:ObsessiveMathsFreak
My personal page. This will be used as a kind of sandbox from time to time, so please excuse the mess. Forum images here
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Namespace Devilry!
[[::Guides:NGE (Episode 02) vs. Evangelion 1.0]] Guides:NGE (Episode 02) vs. Evangelion 1.0
SandBox
Image Woes
Original
Note: In most of these images it's hard to see what we're talking about if you don't click to see the full sized image.
The theory that the Tree of Life tried to form in Antarctica during Second Impact; it was originated by Shin-seiki.
One day, while watching Death, he noticed something curious: a group of wavy lines in the upper left hand corner of the screen as Adam's wings emerge. He checked, and this did not appear in the scene as originally presented in Episode 12, so he concluded that it had been added along with the red soul dots.
He then took a closer look to try and figure out just what it was supposed to be. The more he looked, the more he thought that it looked like the twiggy end of the Tree of Life.
When he posted this conclusion, some of the leading lights of Anime Nation and Eva Monkey Forums were incredulous at first, until Reichu compared a flipped version to a sketch of the Tree of Life from the Groundwork of Evangelion.
She was convinced and became a champion of this theory. Most of the old timers, thewayneiac for example, then followed suit. Much accolades and back-pattings were directed at Shin-seiki for this important discovery.
Unfortunately, a party-pooper extrodinaire with the handle "Kaysow" proceded to decisively demonstrate that what we were looking at was just a flaw in the cell, by posting screencaps of several other instances in Death where the same phenomenon occurs.
He posted about 20 or 30 examples, but two should suffice here.
Faced with this evidence, Shin-seiki was forced to to say, "Never mind."
Attempt At Fix A
Note: In most of these images it's hard to see what we're talking about if you don't click to see the full sized image.
The theory that the Tree of Life tried to form in Antarctica during Second Impact; it was originated by Shin-seiki.
One day, while watching Death, he noticed something curious: a group of wavy lines in the upper left hand corner of the screen as Adam's wings emerge. He checked, and this did not appear in the scene as originally presented in Episode 12, so he concluded that it had been added along with the red soul dots.
He then took a closer look to try and figure out just what it was supposed to be. The more he looked, the more he thought that it looked like the twiggy end of the Tree of Life.
When he posted this conclusion, some of the leading lights of Anime Nation and Eva Monkey Forums were incredulous at first, until Reichu compared a flipped version to a sketch of the Tree of Life from the Groundwork of Evangelion.
She was convinced and became a champion of this theory. Most of the old timers, thewayneiac for example, then followed suit. Much accolades and back-pattings were directed at Shin-seiki for this important discovery.
Unfortunately, a party-pooper extrodinaire with the handle "Kaysow" proceded to decisively demonstrate that what we were looking at was just a flaw in the cell, by posting screencaps of several other instances in Death where the same phenomenon occurs.
He posted about 20 or 30 examples, but two should suffice here.
Faced with this evidence, Shin-seiki was forced to to say, "Never mind."
Attempt At Fix B
Note: In most of these images it's hard to see what we're talking about if you don't click to see the full sized image.
The theory that the Tree of Life tried to form in Antarctica during Second Impact; it was originated by Shin-seiki.
One day, while watching Death, he noticed something curious: a group of wavy lines in the upper left hand corner of the screen as Adam's wings emerge. He checked, and this did not appear in the scene as originally presented in Episode 12, so he concluded that it had been added along with the red soul dots.
He then took a closer look to try and figure out just what it was supposed to be. The more he looked, the more he thought that it looked like the twiggy end of the Tree of Life.
When he posted this conclusion, some of the leading lights of Anime Nation and Eva Monkey Forums were incredulous at first, until Reichu compared a flipped version to a sketch of the Tree of Life from the Groundwork of Evangelion.
She was convinced and became a champion of this theory. Most of the old timers, thewayneiac for example, then followed suit. Much accolades and back-pattings were directed at Shin-seiki for this important discovery.
Unfortunately, a party-pooper extrodinaire with the handle "Kaysow" proceded to decisively demonstrate that what we were looking at was just a flaw in the cell, by posting screencaps of several other instances in Death where the same phenomenon occurs.
He posted about 20 or 30 examples, but two should suffice here.
Faced with this evidence, Shin-seiki was forced to to say, "Never mind."
Testing
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style="vertical-align: top;"Some Text Here. Some Text Here.Some Text Here.Some Text Here.Some Text Here.Some Text Here.Some Text Here.Some Text Here.Some Text Here.Some Text Here.Some Text Here.Some Text Here.Some Text Here.Some Text Here.Some Text Here. |
Note | |
Some Text Here. Some Text Here.Some Text Here.Some Text Here.Some Text Here.Some Text Here.Some Text Here.Some Text Here.Some Text Here.Some Text Here.Some Text Here.Some Text Here.Some Text Here.Some Text Here.Some Text Here. |
Image Table Test
Plain boxes
Test Text A
If two triangles have two sides equal to two sides respectively, and have the angles contained by the equal straight lines equal, then they also have the base equal to the base, the triangle equals the triangle, and the remaining angles equal the remaining angles respectively, namely those opposite the equal sides. Let ABC and DEF be two triangles having the two sides AB and AC equal to the two sides DE and DF respectively, namely AB equal to DE and AC equal to DF, and the angle BAC equal to the angle EDF.
I say that the base BC also equals the base EF, the triangle ABC equals the triangle DEF, and the remaining angles equal the remaining angles respectively, namely those opposite the equal sides, that is, the angle ABC equals the angle DEF, and the angle ACB equals the angle DFE. If the triangle ABC is superposed on the triangle DEF, and if the point A is placed on the point D and the straight line AB on DE, then the point B also coincides with E, because AB equals DE. Again, AB coinciding with DE, the straight line AC also coincides with DF, because the angle BAC equals the angle EDF. Hence the point C also coincides with the point F, because AC again equals DF. But B also coincides with E, hence the base BC coincides with the base EF and equals it. C.N.4 Thus the whole triangle ABC coincides with the whole triangle DEF and equals it. C.N.4 And the remaining angles also coincide with the remaining angles and equal them, the angle ABC equals the angle DEF, and the angle ACB equals the angle DFE. Therefore if two triangles have two sides equal to two sides respectively, and have the angles contained by the equal straight lines equal, then they also have the base equal to the base, the triangle equals the triangle, and the remaining angles equal the remaining angles respectively, namely those opposite the equal sides.
Test Text B
If two triangles have two sides equal to two sides respectively, and have the angles contained by the equal straight lines equal, then they also have the base equal to the base, the triangle equals the triangle, and the remaining angles equal the remaining angles respectively, namely those opposite the equal sides. Let ABC and DEF be two triangles having the two sides AB and AC equal to the two sides DE and DF respectively, namely AB equal to DE and AC equal to DF, and the angle BAC equal to the angle EDF.
I say that the base BC also equals the base EF, the triangle ABC equals the triangle DEF, and the remaining angles equal the remaining angles respectively, namely those opposite the equal sides, that is, the angle ABC equals the angle DEF, and the angle ACB equals the angle DFE. If the triangle ABC is superposed on the triangle DEF, and if the point A is placed on the point D and the straight line AB on DE, then the point B also coincides with E, because AB equals DE. Again, AB coinciding with DE, the straight line AC also coincides with DF, because the angle BAC equals the angle EDF. Hence the point C also coincides with the point F, because AC again equals DF. But B also coincides with E, hence the base BC coincides with the base EF and equals it. C.N.4 Thus the whole triangle ABC coincides with the whole triangle DEF and equals it. C.N.4 And the remaining angles also coincide with the remaining angles and equal them, the angle ABC equals the angle DEF, and the angle ACB equals the angle DFE. Therefore if two triangles have two sides equal to two sides respectively, and have the angles contained by the equal straight lines equal, then they also have the base equal to the base, the triangle equals the triangle, and the remaining angles equal the remaining angles respectively, namely those opposite the equal sides.
Test Text C
If two triangles have two sides equal to two sides respectively, and have the angles contained by the equal straight lines equal, then they also have the base equal to the base, the triangle equals the triangle, and the remaining angles equal the remaining angles respectively, namely those opposite the equal sides. Let ABC and DEF be two triangles having the two sides AB and AC equal to the two sides DE and DF respectively, namely AB equal to DE and AC equal to DF, and the angle BAC equal to the angle EDF.
I say that the base BC also equals the base EF, the triangle ABC equals the triangle DEF, and the remaining angles equal the remaining angles respectively, namely those opposite the equal sides, that is, the angle ABC equals the angle DEF, and the angle ACB equals the angle DFE. If the triangle ABC is superposed on the triangle DEF, and if the point A is placed on the point D and the straight line AB on DE, then the point B also coincides with E, because AB equals DE. Again, AB coinciding with DE, the straight line AC also coincides with DF, because the angle BAC equals the angle EDF. Hence the point C also coincides with the point F, because AC again equals DF. But B also coincides with E, hence the base BC coincides with the base EF and equals it. C.N.4 Thus the whole triangle ABC coincides with the whole triangle DEF and equals it. C.N.4 And the remaining angles also coincide with the remaining angles and equal them, the angle ABC equals the angle DEF, and the angle ACB equals the angle DFE. Therefore if two triangles have two sides equal to two sides respectively, and have the angles contained by the equal straight lines equal, then they also have the base equal to the base, the triangle equals the triangle, and the remaining angles equal the remaining angles respectively, namely those opposite the equal sides.
Test Text D
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If two triangles have two sides equal to two sides respectively, and have the angles contained by the equal straight lines equal, then they also have the base equal to the base, the triangle equals the triangle, and the remaining angles equal the remaining angles respectively, namely those opposite the equal sides. Let ABC and DEF be two triangles having the two sides AB and AC equal to the two sides DE and DF respectively, namely AB equal to DE and AC equal to DF, and the angle BAC equal to the angle EDF.
I say that the base BC also equals the base EF, the triangle ABC equals the triangle DEF, and the remaining angles equal the remaining angles respectively, namely those opposite the equal sides, that is, the angle ABC equals the angle DEF, and the angle ACB equals the angle DFE. If the triangle ABC is superposed on the triangle DEF, and if the point A is placed on the point D and the straight line AB on DE, then the point B also coincides with E, because AB equals DE. Again, AB coinciding with DE, the straight line AC also coincides with DF, because the angle BAC equals the angle EDF. Hence the point C also coincides with the point F, because AC again equals DF. But B also coincides with E, hence the base BC coincides with the base EF and equals it. C.N.4 Thus the whole triangle ABC coincides with the whole triangle DEF and equals it. C.N.4 And the remaining angles also coincide with the remaining angles and equal them, the angle ABC equals the angle DEF, and the angle ACB equals the angle DFE. Therefore if two triangles have two sides equal to two sides respectively, and have the angles contained by the equal straight lines equal, then they also have the base equal to the base, the triangle equals the triangle, and the remaining angles equal the remaining angles respectively, namely those opposite the equal sides.
Main Page Template Test
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